How do I replace all the `None`s with empty strings, and then call some function `f`?

``````[f(x) for x in xs if x is not None else '']
``````

## Solution 1

You can totally do that. It's just an ordering issue:

``````[f(x) if x is not None else '' for x in xs]
``````

In general,

``````[f(x) if condition else g(x) for x in sequence]
``````

And, for list comprehensions with `if` conditions only,

``````[f(x) for x in sequence if condition]
``````

Note that this actually uses a different language construct, a conditional expression, which itself is not part of the comprehension syntax, while the `if` after the `forin` is part of list comprehensions and used to filter elements from the source iterable.

Conditional expressions can be used in all kinds of situations where you want to choose between two expression values based on some condition. This does the same as the ternary operator `?:` that exists in other languages. For example:

``````value = 123
print(value, 'is', 'even' if value % 2 == 0 else 'odd')
``````

## Solution 2

The specific problem has already been solved in previous answers, so I will address the general idea of using conditionals inside list comprehensions.

Here is an example that shows how conditionals can be written inside a list comprehension:

``````X = [1.5, 2.3, 4.4, 5.4, 'n', 1.5, 5.1, 'a']     # Original list

# Extract non-strings from X to new list
X_non_str = [el for el in X if not isinstance(el, str)]  # When using only 'if', put 'for' in the beginning

# Change all strings in X to 'b', preserve everything else as is
X_str_changed = ['b' if isinstance(el, str) else el for el in X]  # When using 'if' and 'else', put 'for' in the end
``````

Note that in the first list comprehension for `X_non_str`, the order is:

expression for item in iterable if condition

and in the last list comprehension for `X_str_changed`, the order is:

expression1 if condition else expression2 for item in iterable

I always find it hard to remember that expression1 has to be before if and expression2 has to be after else. My head wants both to be either before or after.

I guess it is designed like that because it resembles normal language, e.g. "I want to stay inside if it rains, else I want to go outside"

In plain English the two types of list comprehensions mentioned above could be stated as:

With only `if`:

extract_apple for apple in apple_box if apple_is_ripe

and with `if/else`

mark_apple if apple_is_ripe else leave_it_unmarked for apple in apple_box

## Solution 3

Let's use this question to review some concepts. I think it's good to first see the fundamentals so you can extrapolate to different cases.

# Fundamentals

`if/else` statements in list comprehensions involve two things:

• List comprehensions
• Conditional expressions (Ternary operators)

## 1. List comprehensions

They provide a concise way to create lists.

Its structure consists of: "brackets containing an expression followed by a for clause, then zero or more for or if clauses".

### Case 1

Here we have no condition. Each item from the iterable is added to `new_list`.

``````new_list = [expression for item in iterable]
new_list = [x for x in range(1, 10)]
> [1, 2, 3, 4, 5, 6, 7, 8, 9]
``````

### Case 2

Here we have one condition.

Example 1

Condition: only even numbers will be added to `new_list`.

``````new_list = [expression for item in iterable if condition == True]
new_list = [x for x in range(1, 10) if x % 2 == 0]
> [2, 4, 6, 8]
``````

Example 2

Condition: only even numbers that are multiple of 3 will be added to `new_list`.

``````new_list = [expression for item in iterable if condition == True]
new_list = [x for x in range(1, 10) if x % 2 == 0 if x % 3 == 0]
> [6]
``````

But howcome we have one condition if we use two `if` in `new_list`?

The prior expression could be written as:

``````new_list = [x for x in range(1, 10) if x % 2 and x % 3 == 0]
> [6]
``````

We only use one `if` statement.

This is like doing:

``````new_list = []
for x in range(1, 10):
if x % 2 == 0 and x % 3 == 0:
new_list.append(x)
> [6]
``````

Example 3

Just for the sake of argument, you can also use `or`.

Condition: even numbers or numbers multiple of 3 will be added to `new_list`.

``````new_list = [x for x in range(1, 10) if x % 2 == 0 or x % 3 == 0]
> [2, 3, 4, 6, 8, 9]
``````

### Case 3

More than one condition:

Here we need the help of conditional expressions (Ternary operators).

## 2.Conditional Expressions

What are conditional expressions? What the name says: a Python expression that has some condition.

``````<Exp1> if condition else <Exp2>
``````

First the `condition` is evaluated. If `condition` is `True`, then `<Exp1>` is evaluated and returned. If `condition` is `False`, then `<Exp2>` is evaluated and returned.

A conditional expression with more than one condition:

``````<Exp1> if condition else <Exp2> if condition else <Exp3>...
``````

An example from Real Python:

``````age = 12
s = 'minor' if age < 21 else 'adult'
> minor
``````

The value of `s` is conditioned to `age` value.

## 3.List Comprehensions with Conditionals

We put list comprehensions and conditionals together like this.

``````new_list = [<Conditional Expression> for <item> in <iterable>]

new_list = [<Exp1> if condition else <Exp2> if condition else <Exp3> for <item> in <iterable>]
``````

Condition: even numbers will be added as `'even'`, the number three will be added as `'number three'` and the rest will be added as `'odd'`.

``````new_list = ['even' if x % 2 == 0 else 'number three' if x == 3 else 'odd'
for x in range(1, 10)]
> ['odd', 'even', 'number three', 'even', 'odd', 'even', 'odd', 'even', 'odd']
``````

# The answer to the question

``````[f(x) for x in xs if x is not None else '']
``````

Here we have a problem with the structure of the list: `for x in xs` should be at the end of the expression.

Correct way:

``````[f(x) if x is not None else '' for x in xs]
``````

Does Python have a ternary conditional operator?

## Solution 4

One way:

``````def change(x):
if x is None:
return f(x)
else:
return ''

result = [change(x) for x in xs]
``````

Although then you have:

``````result = map(change, xs)
``````

Or you can use a lambda inline.

## Solution 5

Here is another illustrative example:

``````>>> print(", ".join(["ha" if i else "Ha" for i in range(3)]) + "!")
Ha, ha, ha!
``````

It exploits the fact that `if i` evaluates to `False` for `0` and to `True` for all other values generated by the function `range()`. Therefore the list comprehension evaluates as follows:

``````>>> ["ha" if i else "Ha" for i in range(3)]
['Ha', 'ha', 'ha']
``````

## Solution 6

The other solutions are great for a single `if` / `else` construct. However, ternary statements within list comprehensions are arguably difficult to read.

Using a function aids readability, but such a solution is difficult to extend or adapt in a workflow where the mapping is an input. A dictionary can alleviate these concerns:

``````xs = [None, 'This', 'is', 'a', 'filler', 'test', 'string', None]

d = {None: '', 'filler': 'manipulated'}

res = [d.get(x, x) for x in xs]

print(res)

['', 'This', 'is', 'a', 'manipulated', 'test', 'string', '']
``````

## Solution 7

It has to do with how the list comprehension is performed.

Keep in mind the following:

``````[ expression for item in list if conditional ]
``````

Is equivalent to:

``````for item in list:
if conditional:
expression
``````

Where the `expression` is in a slightly different format (think switching the subject and verb order in a sentence).

Therefore, your code `[x+1 for x in l if x >= 45]` does this:

``````for x in l:
if x >= 45:
x+1
``````

However, this code `[x+1 if x >= 45 else x+5 for x in l]` does this (after rearranging the `expression`):

``````for x in l:
if x>=45: x+1
else: x+5
``````

## Solution 8

``````[f(x) if x != None else '' for x in xs]
``````

Syntax for list comprehension:

``````[item if condition else item for item in items]
[f(item) if condition else value for item in items]
[item if condition for item in items]
[value if condition else value1 if condition1 else value2]
``````

## Solution 9

Make a list from items in an iterable

It seems best to first generalize all the possible forms rather than giving specific answers to questions. Otherwise, the reader won't know how the answer was determined. Here are a few generalized forms I thought up before I got a headache trying to decide if a final else' clause could be used in the last form.

``````[expression1(item)                                        for item in iterable]

[expression1(item) if conditional1                        for item in iterable]

[expression1(item) if conditional1 else expression2(item) for item in iterable]

[expression1(item) if conditional1 else expression2(item) for item in iterable if conditional2]
``````

The value of `item` doesn't need to be used in any of the conditional clauses. A `conditional3` can be used as a switch to either add or not add a value to the output list.

For example, to create a new list that eliminates empty strings or whitespace strings from the original list of strings:

``````newlist = [s for s in firstlist if s.strip()]
``````

## Solution 10

There isn't any need for ternary if/then/else. In my opinion your question calls for this answer:

``````row = [unicode((x or '').strip()) for x in row]
``````

## Solution 11

You can combine conditional logic in a comprehension:

`````` ps = PorterStemmer()
stop_words_english = stopwords.words('english')
best = sorted(word_scores.items(), key=lambda x: x[1], reverse=True)[:10000]
bestwords = set([w for w, s in best])

def best_word_feats(words):
return dict([(word, True) for word in words if word in bestwords])

# with stemmer
def best_word_feats_stem(words):
return dict([(ps.stem(word), True) for word in words if word in bestwords])

# with stemmer and not stopwords
def best_word_feats_stem_stop(words):
return dict([(ps.stem(word), True) for word in words if word in bestwords and word not in stop_words_english])
``````

## Solution 12

``````# coding=utf-8

def my_function_get_list():
my_list = [0, 1, 2, 3, 4, 5]

# You may use map() to convert each item in the list to a string,
# and then join them to print my_list

print("Affichage de my_list [{0}]".format(', '.join(map(str, my_list))))

return my_list

my_result_list = [
(
number_in_my_list + 4,  # Condition is False : append number_in_my_list + 4 in my_result_list
number_in_my_list * 2  # Condition is True : append number_in_my_list * 2 in my_result_list
)

[number_in_my_list % 2 == 0]  # [Condition] If the number in my list is even

for number_in_my_list in my_function_get_list()  # For each number in my list
]

print("Affichage de my_result_list [{0}]".format(', '.join(map(str, my_result_list))))
``````

(venv) \$ python list_comp.py
Affichage de my_list [0, 1, 2, 3, 4, 5]
Affichage de my_result_list [0, 5, 4, 7, 8, 9]

So, for you: `row = [('', unicode(x.strip()))[x is not None] for x in row]`