I am using following options

set -o pipefail
set -e

In bash script to stop execution on error. I have ~100 lines of script executing and I don't want to check return code of every line in the script.

But for one particular command, I want to ignore the error. How can I do that?

Solution 1

The solution:

particular_script || true


$ cat /tmp/1.sh

set -e

echo one
particular_script || true
echo two
echo three

$ bash /tmp/1.sh

three will be never printed.

Also, I want to add that when pipefail is on, it is enough for shell to think that the entire pipe has non-zero exit code when one of commands in the pipe has non-zero exit code (with pipefail off it must the last one).

$ set -o pipefail
$ false | true ; echo $?
$ set +o pipefail
$ false | true ; echo $?

Solution 2

Just add || true after the command where you want to ignore the error.

Solution 3

Don't stop and also save exit status

Just in case if you want your script not to stop if a particular command fails and you also want to save error code of failed command:

set -e
command || EXIT_CODE=$?

Solution 4

More concisely:

! particular_script

From the POSIX specification regarding set -e (emphasis mine):

When this option is on, if a simple command fails for any of the reasons listed in Consequences of Shell Errors or returns an exit status value >0, and is not part of the compound list following a while, until, or if keyword, and is not a part of an AND or OR list, and is not a pipeline preceded by the ! reserved word, then the shell shall immediately exit.

Solution 5

Instead of "returning true", you can also use the "noop" or null utility (as referred in the POSIX specs) : and just "do nothing". You'll save a few letters. :)

#!/usr/bin/env bash
set -e
man nonexistentghing || :
echo "It's ok.."

Solution 6

If you want to prevent your script failing and collect the return code:

command () {
    return 1  # or 0 for success

set -e

command && returncode=$? || returncode=$?
echo $returncode

returncode is collected no matter whether command succeeds or fails.

Solution 7

Thanks for the simple solution here from above:

<particular_script/command> || true

The following construction could be used for additional actions/troubleshooting of script steps and additional flow control options:

if <particular_script/command>
   echo "<particular_script/command> is fine!"
   echo "<particular_script/command> failed!"
   #exit 1

We can brake the further actions and exit 1 if required.

Solution 8

No solutions worked for me from here, so I found another one:

set +e
find "./csharp/Platform.$REPOSITORY_NAME/obj" -type f -iname "*.cs" -delete
find "./csharp/Platform.$REPOSITORY_NAME.Tests/obj" -type f -iname "*.cs" -delete
set -e

You can turn off failing on errors by set +e this will now ignore all errors after that line. Once you are done, and you want the script to fail again on any error, you can use set -e.

After applying set +e the find does not fail the whole script anymore, when files are not found. At the same time, error messages from find are still printed, but the whole script continues to execute. So it is easy to debug if that causes the problem.

This is useful for CI & CD (for example in GitHub Actions).

Solution 9

output=$(*command* 2>&1) && exit_status=$? || exit_status=$?
echo $output
echo $exit_status

Example of using this to create a log file

timestamp=$(date '+%D %T') #mm/dd/yy HH:MM:SS
echo -e "($timestamp) $event" >> "$log_file"

output=$(*command* 2>&1) && exit_status=$? || exit_status=$?

if [ "$exit_status" = 0 ]
        event="ERROR $output"

Solution 10

I have been using the snippet below when working with CLI tools and I want to know if some resource exist or not, but I don't care about the output.

if [ -z "$(cat no_exist 2>&1 >/dev/null)" ]; then
    echo "none exist actually exist!"

Solution 11

while || true is preferred one, but you can also do

var=$(echo $(exit 1)) # it shouldn't fail

Solution 12

I kind of like this solution :

: `particular_script`

The command/script between the back ticks is executed and its output is fed to the command ":" (which is the equivalent of "true")

$ false
$ echo $?
$ : `false`
$ echo $?

edit: Fixed ugly typo