I have two date like:

String date_1="yyyyMMddHHmmss";
String date_2="yyyyMMddHHmmss";

I want to print the difference like:

2d 3h 45m

How can I do that? Thanks!

Solution 1

DateTimeUtils obj = new DateTimeUtils();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/M/yyyy hh:mm:ss");

try {
    Date date1 = simpleDateFormat.parse("10/10/2013 11:30:10");
    Date date2 = simpleDateFormat.parse("13/10/2013 20:35:55");

    obj.printDifference(date1, date2);

} catch (ParseException e) {
    e.printStackTrace();
}

//1 minute = 60 seconds
//1 hour = 60 x 60 = 3600
//1 day = 3600 x 24 = 86400
public void printDifference(Date startDate, Date endDate) { 
    //milliseconds
    long different = endDate.getTime() - startDate.getTime();

    System.out.println("startDate : " + startDate);
    System.out.println("endDate : "+ endDate);
    System.out.println("different : " + different);

    long secondsInMilli = 1000;
    long minutesInMilli = secondsInMilli * 60;
    long hoursInMilli = minutesInMilli * 60;
    long daysInMilli = hoursInMilli * 24;

    long elapsedDays = different / daysInMilli;
    different = different % daysInMilli;

    long elapsedHours = different / hoursInMilli;
    different = different % hoursInMilli;

    long elapsedMinutes = different / minutesInMilli;
    different = different % minutesInMilli;

    long elapsedSeconds = different / secondsInMilli;

    System.out.printf(
        "%d days, %d hours, %d minutes, %d seconds%n", 
        elapsedDays, elapsedHours, elapsedMinutes, elapsedSeconds);
}

out put is :

startDate : Thu Oct 10 11:30:10 SGT 2013
endDate : Sun Oct 13 20:35:55 SGT 2013
different : 291945000
3 days, 9 hours, 5 minutes, 45 seconds

Solution 2

Date userDob = new SimpleDateFormat("yyyy-MM-dd").parse(dob);
Date today = new Date();
long diff =  today.getTime() - userDob.getTime();
int numOfDays = (int) (diff / (1000 * 60 * 60 * 24));
int hours = (int) (diff / (1000 * 60 * 60));
int minutes = (int) (diff / (1000 * 60));
int seconds = (int) (diff / (1000));

Solution 3

Short & Sweet:

/**
 * Get a diff between two dates
 *
 * @param oldDate the old date
 * @param newDate the new date
 * @return the diff value, in the days
 */
public static long getDateDiff(SimpleDateFormat format, String oldDate, String newDate) {
    try {
        return TimeUnit.DAYS.convert(format.parse(newDate).getTime() - format.parse(oldDate).getTime(), TimeUnit.MILLISECONDS);
    } catch (Exception e) {
        e.printStackTrace();
        return 0;
    }
}

Usage:

int dateDifference = (int) getDateDiff(new SimpleDateFormat("dd/MM/yyyy"), "29/05/2017", "31/05/2017");
System.out.println("dateDifference: " + dateDifference);

Output:

dateDifference: 2

Kotlin Version:

@ExperimentalTime
fun getDateDiff(format: SimpleDateFormat, oldDate: String, newDate: String): Long {
    return try {
        DurationUnit.DAYS.convert(
            format.parse(newDate).time - format.parse(oldDate).time,
            DurationUnit.MILLISECONDS
        )
    } catch (e: Exception) {
        e.printStackTrace()
        0
    }
}

Solution 4

This works and convert to String as a Bonus ;)

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.activity_main);

    try {
        //Dates to compare
        String CurrentDate=  "09/24/2015";
        String FinalDate=  "09/26/2015";

        Date date1;
        Date date2;

        SimpleDateFormat dates = new SimpleDateFormat("MM/dd/yyyy");

        //Setting dates
        date1 = dates.parse(CurrentDate);
        date2 = dates.parse(FinalDate);

        //Comparing dates
        long difference = Math.abs(date1.getTime() - date2.getTime());
        long differenceDates = difference / (24 * 60 * 60 * 1000);

        //Convert long to String
        String dayDifference = Long.toString(differenceDates);

        Log.e("HERE","HERE: " + dayDifference);

    } catch (Exception exception) {
        Log.e("DIDN'T WORK", "exception " + exception);
    }
}

Solution 5

It will give you difference in months

long milliSeconds1 = calendar1.getTimeInMillis();
long milliSeconds2 = calendar2.getTimeInMillis();
long periodSeconds = (milliSeconds2 - milliSeconds1) / 1000;
long elapsedDays = periodSeconds / 60 / 60 / 24;

System.out.println(String.format("%d months", elapsedDays/30));

Solution 6

Here is the modern answer. Its good for anyone who either uses Java 8 or later (which doesnt go for most Android phones yet) or is happy with an external library.

    String date1 = "20170717141000";
    String date2 = "20170719175500";

    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss");
    Duration diff = Duration.between(LocalDateTime.parse(date1, formatter), 
                                     LocalDateTime.parse(date2, formatter));

    if (diff.isZero()) {
        System.out.println("0m");
    } else {
        long days = diff.toDays();
        if (days != 0) {
            System.out.print("" + days + "d ");
            diff = diff.minusDays(days);
        }
        long hours = diff.toHours();
        if (hours != 0) {
            System.out.print("" + hours + "h ");
            diff = diff.minusHours(hours);
        }
        long minutes = diff.toMinutes();
        if (minutes != 0) {
            System.out.print("" + minutes + "m ");
            diff = diff.minusMinutes(minutes);
        }
        long seconds = diff.getSeconds();
        if (seconds != 0) {
            System.out.print("" + seconds + "s ");
        }
        System.out.println();
    }

This prints

2d 3h 45m 

In my own opinion the advantage is not so much that it is shorter (its not much), but leaving the calculations to an standard library is less errorprone and gives you clearer code. These are great advantages. The reader is not burdened with recognizing constants like 24, 60 and 1000 and verifying that they are used correctly.

I am using the modern Java date & time API (described in JSR-310 and also known under this name). To use this on Android under API level 26, get the ThreeTenABP, see this question: How to use ThreeTenABP in Android Project. To use it with other Java 6 or 7, get ThreeTen Backport. With Java 8 and later it is built-in.

With Java 9 it will be still a bit easier since the Duration class is extended with methods to give you the days part, hours part, minutes part and seconds part separately so you dont need the subtractions. See an example in my answer here.

Solution 7

I use this: send start and end date in millisecond

public int GetDifference(long start,long end){
    Calendar cal = Calendar.getInstance();
    cal.setTimeInMillis(start);
    int hour = cal.get(Calendar.HOUR_OF_DAY);
    int min = cal.get(Calendar.MINUTE);
    long t=(23-hour)*3600000+(59-min)*60000;

    t=start+t;

    int diff=0;
    if(end>t){
        diff=(int)((end-t)/ TimeUnit.DAYS.toMillis(1))+1;
    }

    return  diff;
}

Solution 8

You can calculate the difference in time in miliseconds using this method and get the outputs in seconds, minutes, hours, days, months and years.

You can download class from here: DateTimeDifference GitHub Link

  • Simple to use
long currentTime = System.currentTimeMillis();
long previousTime = (System.currentTimeMillis() - 864000000); //10 days ago

Log.d("DateTime: ", "Difference With Second: " + AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.SECOND));
Log.d("DateTime: ", "Difference With Minute: " + AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.MINUTE));
  • You can compare the example below
if(AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.MINUTE) > 100){
    Log.d("DateTime: ", "There are more than 100 minutes difference between two dates.");
}else{
    Log.d("DateTime: ", "There are no more than 100 minutes difference between two dates.");
}

Solution 9

Try this out.

int day = 0;
        int hh = 0;
        int mm = 0;
        try {
            SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy 'at' hh:mm aa");
            Date oldDate = dateFormat.parse(oldTime);
            Date cDate = new Date();
            Long timeDiff = cDate.getTime() - oldDate.getTime();
            day = (int) TimeUnit.MILLISECONDS.toDays(timeDiff);
            hh = (int) (TimeUnit.MILLISECONDS.toHours(timeDiff) - TimeUnit.DAYS.toHours(day));
            mm = (int) (TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff)));



        } catch (ParseException e) {
            e.printStackTrace();
        }

        if (mm <= 60 && hh!= 0) {
            if (hh <= 60 && day != 0) {
                return day + " DAYS AGO";
            } else {
                return hh + " HOUR AGO";
            }
        } else {
            return mm + " MIN AGO";
        }

Solution 10

DateTime start = new DateTime(2013, 10, 20, 5, 0, 0, Locale);
DateTime end = new DateTime(2013, 10, 21, 13, 0, 0, Locale);
Days.daysBetween(start.toLocalDate(), end.toLocalDate()).getDays()

it returns how many days between given two dates, where DateTime is from joda library

Solution 11

I arranged a little. This works great.

@SuppressLint("SimpleDateFormat") SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd MM yyyy");
    Date date = new Date();
    String dateOfDay = simpleDateFormat.format(date);

    String timeofday = android.text.format.DateFormat.format("HH:mm:ss", new Date().getTime()).toString();

    @SuppressLint("SimpleDateFormat") SimpleDateFormat dateFormat = new SimpleDateFormat("dd MM yyyy hh:mm:ss");
    try {
        Date date1 = dateFormat.parse(06 09 2018 + " " + 10:12:56);
        Date date2 = dateFormat.parse(dateOfDay + " " + timeofday);

        printDifference(date1, date2);

    } catch (ParseException e) {
        e.printStackTrace();
    }

@SuppressLint("SetTextI18n")
private void printDifference(Date startDate, Date endDate) {
    //milliseconds
    long different = endDate.getTime() - startDate.getTime();

    long secondsInMilli = 1000;
    long minutesInMilli = secondsInMilli * 60;
    long hoursInMilli = minutesInMilli * 60;
    long daysInMilli = hoursInMilli * 24;

    long elapsedDays = different / daysInMilli;
    different = different % daysInMilli;

    long elapsedHours = different / hoursInMilli;
    different = different % hoursInMilli;

    long elapsedMinutes = different / minutesInMilli;
    different = different % minutesInMilli;

    long elapsedSeconds = different / secondsInMilli;

Toast.makeText(context, elapsedDays + " " + elapsedHours + " " + elapsedMinutes + " " + elapsedSeconds, Toast.LENGTH_SHORT).show();
}

Solution 12

When you use Date() to calculate the difference in hours is necessary configure the SimpleDateFormat() in UTC otherwise you get one hour error due to Daylight SavingTime.

Solution 13

You can generalize this into a function that lets you choose the output format

private String substractDates(Date date1, Date date2, SimpleDateFormat format) {
    long restDatesinMillis = date1.getTime()-date2.getTime();
    Date restdate = new Date(restDatesinMillis);

    return format.format(restdate);
}

Now is a simple function call like this, difference in hours, minutes and seconds:

SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try {
    Date date1 = formater.parse(dateEnd);
    Date date2 = formater.parse(dateInit);

    String result = substractDates(date1, date2, new SimpleDateFormat("HH:mm:ss"));

    txtTime.setText(result);
} catch (ParseException e) {
    e.printStackTrace();
}

Solution 14

Here's the simple solution:

fun printDaysBetweenTwoDates(): Int {
        val dateFormat = SimpleDateFormat("dd-MM-yyyy", Locale.ENGLISH)
        val endDateInMilliSeconds = dateFormat.parse("26-02-2022")?.time ?: 0
        val startDateInMilliSeconds = dateFormat.parse("18-02-2022")?.time ?: 0
        return getNumberOfDaysBetweenDates(startDateInMilliSeconds, endDateInMilliSeconds)
    }

 private fun getNumberOfDaysBetweenDates(
        startDateInMilliSeconds: Long,
        endDateInMilliSeconds: Long
    ): Int {
        val difference = (endDateInMilliSeconds - startDateInMilliSeconds) / (1000 * 60 * 60 * 24).toDouble()
        val noOfDays = Math.ceil(difference)
        return (noOfDays).toInt()
    }